Math, asked by arjun2611kumar, 3 months ago

AP 3
(iv) If PQ || BC and then AC such that AQ = 2.1 cm,
PB 5
is equal to
[1]
А
P Р
B
С
(a) 5.2 cm
(c) 5.8 cm
(b) 5.4 cm
(d) 5.6 cm​

Answers

Answered by madhumitaghadai8
0

Answer:

5.6cm

Step-by-step explanation:

PQ || BC

AP/PB = 3/5

AQ = 2.1 cm

\textbf{To find :-}To find :-

AC = ?

\textbf{Solution :-}Solution :-

By applying \textbf{BPT Theorem}BPT Theorem , we get

AP/PB = AQ/QC

3/5 = 2.1/QC

QC = (2.1 × 5)/3

QC = 3.5 cm

Now,

AC = AQ + QC

AC = 2.1 + 3.5

\textbf{AC = 5.6 cm}AC = 5.6 cm

\textbf{Hope this helps you.}Hope this helps you

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