AP=3cm,AR=4.5cm,AQ=6cm,AB=5cm andAC=10cm.find the length of AD
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Solution:-
Given
AP=3cm
PB=2cm
AQ=6cm
QC=4cm
AR=4.5cm
AD=?
in ∆ ABD
PR is parallel to BD
( PQ || BC as AP/PB= AQ /QC = 3/2 from BPT )
There fore ,
By ∆ BPT ,
AP/PB = AR /RD
3/2=4.5/RD
3RD = 9
RD = 3
AD = AR+RD
AD = 4.5+3=7.5 cm
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@GauravSaxena01
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