AP =4cm,PB=6cm,PC=2cm find the area of circle
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Step-by-step explanation:
here is solution
see the attachment
here some calculations mistake are there
200/5=50
but all procedure will be same
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Gɪᴠᴇɴ :-
- AP = 4 cm.
- PB = 6 cm.
- PC = 2 cm.
Tᴏ Fɪɴᴅ :-
- Area of circle ?
Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-
- Intersect chord Theoram Say That :- AP * PB = DP * PC .
- 4r² = AP² + PB² + DP² + PC² . (Shortcut).
- Area of Circle = π * r²
Sᴏʟᴜᴛɪᴏɴ :-
Putting all values we get,
→ AP * PB = DP * PC
→ 4 * 6 = DP * 2
→ DP = 12cm.
Now, Let radius of circle is r cm..
Than,
→ 4r² = AP² + PB² + DP² + PC²
→ 4r² = 4² + 6² + 2² + 12²
→ 4r² = 16 + 36 + 4 + 144
→ 4r² = 200
→ r² = 50
→ r = 5√2 cm.
Therefore,
→ Area of circle = πr² = 3.14 * (5√2)² = 3.14 * 50 = 157cm².(Ans.)
Hence, Area of circle will be 157cm².
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