ap = 6 , 12,18,24 ,... ,120 . find sum of nth term
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AP = 6 , 12 , 18 , 24 , ...120.
Here,
First term ( a ) = 6
Common difference ( d ) = 6
Last term ( Tn ) = 120
a + ( n - 1 ) × d = 120
6 + ( n - 1 ) 6 = 120
6 + 6n - 6 = 120
6n = 120
n = 20.
Therefore,
Sn = n/2 × ( First term + Last term )
S20 = 20/2 × ( 6 + 120 )
=> 10 × 126
=> 1260.
AP = 6 , 12 , 18 , 24 , ...120.
Here,
First term ( a ) = 6
Common difference ( d ) = 6
Last term ( Tn ) = 120
a + ( n - 1 ) × d = 120
6 + ( n - 1 ) 6 = 120
6 + 6n - 6 = 120
6n = 120
n = 20.
Therefore,
Sn = n/2 × ( First term + Last term )
S20 = 20/2 × ( 6 + 120 )
=> 10 × 126
=> 1260.
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