Question

AP a7=45 and a9 =57 find the AP

Answer 1

prefer the image for the solution

Answer 2

Answer:

Step-by-step explanation:

a7=45 and a9=57

an=a+{n-1}d          

Therefore, a7=a+6d

                  a9=a+8d

By Elimination Method,

a+6d=45

a+8d=57

-  -    = -

  -2d=-12

Therefore, d=6

Now, a+6d=45

         a+6x6=45    {since, d=6}

         a=45-36

         a=9                

Therefore, the required A.P is

9,15,21,27,.........

HOPE THIS HELPS YOU!!!!!!