Question

AP (ADVANCED PLACEMENT) 2:TRIGONOMETRY EXTREMELY HARD!!!!
n 2+i\pi} + e^{{-}{\ln 2}-i\pi}}{2} ={\ln 2}e^\pi} +) = \bigl(6x^2y^2-x^4-y^4\bigr) + i\,kxy\bigl(x^2-y^2\bigr). \] ... Then \(\ k(x^3-3xy^2) = 12xy^2-4x^3\), so \(\f{$k = -4$}\).{1}{z^2}\,dz\), where \(C\) 1 ft3 = 1728 in3, 1 ft3 = 28,316.8 cm3, and 1 lb=453.5 gis the contour \(z(t) = t^2 + i \cos(\pi t). What is the overall turnover rate for
Valid Invalid
2Ph=a+b
Valid – 2 cap p over h is equal to A plus b
Invalid – 2 cap p over h is equal to A plus b
h=a+b2P
Valid – h is equal to the fraction with numerator A plus b and denominator 2 cap p
Invalid – h is equal to the fraction with numerator A plus b and denominator 2 cap p
4.085– cap p is equal to 1 half A h plus b h
– cap p is equal to 1 half A h plus b h
2P=(a+b)h
I will Give 71 points and Brainliest!!!!

Answer 1

Answer: Your answer is...............

\ \sin A = \cos^2 AsinA=cossinA=1−sin    

splaystyle \sin^2 A = \cos^4 Asin  

\1 - \cos ^2 A = \cos^4 A1−cos

\ 1 = \cos^4 A + \cos^2 A1=cos  

4

=/?/

A+cos  

\displaystyle 1^3 = (\cos^4 A + \cos^2 A)^31

 by formula \ A+3cos

A+3cos A+cos

A+cos (a+b)^3(a+b)   =(cos  

\ 1 = \cos^{12} A + 3 \cos^{10} A +3 \cos^8 A + \cos^6 A1=cos  

e1 onto the other side we get the condition as given as in the question. Comparing the variables we get \ a = 1a=1, \style&formatt b = 3b=3, \de c = 3c=3, \ d = 1d=1 hence the value of \ b +\frac{c}{a}+b = \frac{3 + 3}{1 + 1} = \frac{6}{2} = pi8*****************************

We are in the same class!!!!!!!!!!

Answer 2

Answer:

please refer the attachment for your answer