AP and AQ are tangents drawn from a point A to a circle with centre O and radius 9 cm .If OA =15 cm ,then AP+AQ?
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Answered by
14
Since tangents drawn from an external point will be equal in length,
AP = AQ
Since, AP = 12
AQ = 12
AP + AQ = 12 + 12
AP + AQ = 24
AP = AQ
Since, AP = 12
AQ = 12
AP + AQ = 12 + 12
AP + AQ = 24
dhruv8667:
how AP comes 12??????? how can u write it directly???
Answered by
31
here's your answer dude
Since AP & AQ are 2 tangents to a circle
radius i.e. PO & QO
OA =15 cm
AP & AQ are tangents to a circle at point P&Q respectively.
We have to use tangent segment theorem and phytagores theorem to solve this
OA(square)=PO(square)+AP(square)
225=81+AP(square)
AP(square)=225-81
AP(square)=144
AP = 12
by theoremof tangent segment,
AP=AQ
AP+AQ=12+12=24
plz mark as brainliest
Since AP & AQ are 2 tangents to a circle
radius i.e. PO & QO
OA =15 cm
AP & AQ are tangents to a circle at point P&Q respectively.
We have to use tangent segment theorem and phytagores theorem to solve this
OA(square)=PO(square)+AP(square)
225=81+AP(square)
AP(square)=225-81
AP(square)=144
AP = 12
by theoremof tangent segment,
AP=AQ
AP+AQ=12+12=24
plz mark as brainliest
thank you I'm glad u like it
though i had some other doubt. yout answer was impressive in my book it given that AP and PQ are tangents from point A which i think is not possible there might br a printing mistake
hats off to your answer
thank you very much broo
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