Math, asked by Kakati, 1 year ago

AP and AQ are tangents drawn from a point A to a circle with centre O and radius 9 cm .If OA =15 cm ,then AP+AQ?

Answers

Answered by ravi34287

Since tangents drawn from an external point will be equal in length,

AP = AQ

Since, AP = 12

AQ = 12

AP + AQ = 12 + 12

AP + AQ = 24

dhruv8667: how AP comes 12??????? how can u write it directly???

Answered by dhruv8667

here's your answer dude
Since AP & AQ are 2 tangents to a circle
radius i.e. PO & QO
OA =15 cm
AP & AQ are tangents to a circle at point P&Q respectively.
We have to use tangent segment theorem and phytagores theorem to solve this
OA(square)=PO(square)+AP(square)
225=81+AP(square)
AP(square)=225-81
AP(square)=144
AP = 12
by theoremof tangent segment,
AP=AQ
AP+AQ=12+12=24
plz mark as brainliest

dhruv8667: thank you I'm glad u like it

Kakati: though i had some other doubt. yout answer was impressive in my book it given that AP and PQ are tangents from point A which i think is not possible there might br a printing mistake

Kakati: hats off to your answer

dhruv8667: thank you very much broo

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