Question

AP and AQ are two tangents to the circle with centre at O, from an
exterior point A. If Z PAQ = 82°, then ZPOQ is -​

Answer 1

Answer:

∠A+∠P+∠Q+∠O=360  

(sum of Angles in a

quadrilateral APOQ)

⇒∠A+90∘+90∘+110∘=360∘

⇒∠A=70∘

∠PAQ=70∘      (B

Step-by-step explanation: