AP and BP are the bisectors of ∠A and ∠B of quadrilateral ABCD. If ∠D = 100° <br /><br />and ∠C = 100°, find the measure of ∠APB.
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If AP and BP are angle bisector, then
∠1=∠2=∠A/2
∠3=∠4=∠B/2
And Consecutive angles are supplementary
∴∠1+∠2=180−(∠3+∠4)
∠A=180−∠B
From the figure, ∠APB=180−(∠1+∠3)
=180−(180−(∠2+∠4))
=∠2+∠4=∠A/2+∠B/2
⇒2∠APB=∠A+∠B
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