Question

ap----》arithmetic progression ​​

Answer 1

Answer:

Rs. 27,750

Step-by-step explanation:

Arranging the given question in sequence;

200, 250, 300,

t1=a=200

t2=250

t3=300

d=?

t30=b=?

S30=?

Now,

d= t2-t1 = 250-200 = 50

t30 = a+29d = 200 + 29*50 = 200 + 1450 = 1650

S30 = (n/2)(a+b) = (30/2)(200+1650) = 15*1850 = 27750

∴The contractor has to pay Rs.27,750 if he has delayed the work for 30 days.