Question

AP CONSIST OF 50 TERMS IN WHICH 3rd TERM IS 12 AND THE LAST TERM IS 106 FIND THE 29th TERM ?

Answer 1

the correct answer should be 64 , 29th term is 64

Answer 2

64

Step-by-step explanation:

Let the first term of the AP be 'a' and common difference be 'd'.

3rd term = 12    ⇒ a + 2d = 12     ...(1)

50th term = 106  ⇒ a + 49d = 106   ...(2)

Subtract (1) from (2),  we get 47d = 94

         ⇒ d = 94/47

         ⇒ d = 2

Hence, in (1),   a + 2(2) = 12    ⇒ a = 8

∴ 29th term = a + 28d

                   = 8 + 28(2)

                   = 64