Question

Ap Gp.
Question No. 22​

Answer 1

Answer:

Step-by-step explanation:

Let numbers be a,ar,ar²

now:

a+ar+ar²=70

a(1+r+r²)=70

a=70/1+r+r²

4a,5ar,4ar² are in AP

5ar-4a=4ar²-5ar

=10ar=4ar²+4a

=4ar²-10ar+4a=0

=2a(2r²-5r+2)=0

=2(70/1+r+r²)(2r²-5r+2)=0

=280r²-700r+280=0

on solving;

r=2 and a=10

so numbers are=10,20,40