AP gyat Kijiye Jiska Teesra pad five aur satavan pad 9
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3rd term = 5 and 7th term = 9 ( given )
now a+2d=5
- a= 5-2d →(i)
then a+6d=9
5-2d+6d=9. (from equation i )
. 5+4d=9
. 4d= 9-5
. 4d= 4
. d=1
now a= 5-2.1
. a=5-2=3
Hence, AP = 3,4,5,6,........
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