Question

Ap has a 3rd term 13 and the last term is 148 . If the c.d is 5 then the number of term is

Answer 1

Answer: The number of term is 30.

Step-by-step explanation:

a = first term, d = common difference ,n = term of the A.P.

d = 5

3rd term = a + 2d = 13

last term = $a_{n$ = a + (n - 1)d = 148

To find a,

a + 2d = 13

a + 2(5) = 13

a + 10 = 13

a = 13 - 10

a = 3

Now,find n

$a_{n}$ = a + (n - 1)d

148 = 3 + (n - 1)5

148 - 3 = (n - 1)5

145/5 = n - 1

29 = n - 1

n = 29 + 1

n = 30

I hope this answer is helpful for you.