Question

ap is 43 common difference is 7
find 10 th term?
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Answer 1

Answer :

$\large{\dag\:\:\boxed{\bigstar\:\:a_{10}\:=\:106\:\:\bigstar}\:\:\dag}$

Correct Question :–

a is 43 and the common difference is 7 then find 10th Term .

Explanation :

Given :–

• a = 43 (1st Term is 43 .)

• d = 7 (Common Difference is 7 . )

To Find :–

• a₁₀ (10th Term of this A.P.)

Formula Applied :–

• $\boxed{\bf{\star\:\:a_n\:=\:a\:+\:(n\:-\:1)d\:\:\star}}$

Solution :–

We have a = 43 , n = 10 and d = 7 .

Putting these Values in the Formula :

$\rightarrow\sf{a_n\:=\:a\:+\:(n\:-\:1)d}$

$\rightarrow\sf{a_{10}\:=\:43\:+\:(10\:-\:1)(7)}$

$\rightarrow\sf{a_{10}\:=\:43\:+\:(9\:\times\:7)}$

$\rightarrow\sf{a_{10}\:=\:43\:+\:63}$

$\rightarrow\boxed{\bf{a_{10}\:=\:106}}$

∴ 10th Term of this A.P. is 106 .

Answer 2

Question:

In an A.P. , a is 43 and common difference is 7, find the 10 th term.

To find:

$\bigstar {10}^{th} \: term \: \underline{t _{10} = ?}$

Answer:

${10}^{th} \: term \: is \: \underline{ \sf\pink{ \: 106} \: }$

Given:

$First \: term \: \underline{ \: (a) = 43 \: }$

$Common \: difference \:\underline{ \: (d) = 7 \: }$

Step-by-step explanation:

We know that, ${n}^{th} \: term \: formula$

$\boxed{t _{n} = a + (n - 1)d}$

$\implies t_{10} = a + 9d$

Now substituting the values,

$\implies 43 + 9(7)$

$\implies 43 + 63$

$\implies \boxed{ t_{10} = 106}$

$\therefore {10}^{th} \: term \: is \: \underline{ \bf \: 106 \: }$

Formula used:

$\bigstar t _{n} = a + (n - 1)d$

More information:

★ Arithmetic Progression :

In a sequence the difference between the two consecutive terms are equal, it is called Arithmetic Progression .

★ Common difference :

$d = t_{2} - t _{1}$

★ General form :

$a,a+d,a+2d,a+3d,.....$

★ No. of terms :

$n = \frac{l - a}{d} + 1$

⚠️Note⚠️

${n}^{th}\:term$ can also be indicate as $a_{n}\:or\:t_{n}$