Question

AP is a median of traingle ABC prove that AB, BC, AC> 2AP​

Answer 1

Step-by-step explanation:

SOLUTION:-

IN TRIANGLE ABM

AB+ BM > AM ➡️(1)

IN TRIANGLE ACM

AC + CM > AM ➡️(2)

BY ADDING THE EQUATION 1 & 2 WE GET,

AB + AC +( BM+CM) > 2AM

WHERE BM +CM = BC ( ACC. TO FIGURE)

SO, AB + BC + CA > 2 AM

HENCE PROVED!!

Answer 2

Answer:

AB+BC+CA> 2 AM

Step-by-step explanation:

Hope this helps mate