AP is a tangent to a point A on the circle with centre O from an external point P. OP intersects the circle at B. If PA = 4 cm, PB = 2 cm, find the radius. (No diagram is given for the question)
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Answer:
2√2
Step-by-step explanation:
PA = 4cm , PB = 2cm
Radius of circle
r =√(PA×PB)= √(2×4) = 2√2cm Ans.
OR
PA/OB= OA/PB
4/r = r/2 => r^2 = 8 => r = √8 = 2√2cm
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