Question

ap is equal to 6.2 cm long tangent to a circle of radius 3.1 cm at P how far is P from O​

Answer 1

Answer:

OP = 3.1 cm

OP = 3.1√5 cm

Step-by-step explanation:

Assuming O is center of circle

& AP is tangent  to circle at P

=> P lies on circle

=> OP = Radius of circle

=> OP = 3.1 cm

Now Considering AP is tangent at point A

then OA = Radius = 3.1 cm

AP = 6.2 cm  given

∠OAP = 90°  ( Tangent)

=> OP² = OA² + AP²

=> OP² = 3.1² + 6.2²

=> OP² = 3.1²(1 + 4)

=> OP² = 3.1² (5)

=> OP = 3.1√5 cm

Answer 2

Answer:

Assuming O is center of circle

& AP is tangent to circle at P

=> P lies on circle

=> OP = Radius of circle

=> OP = 3.1 cm

Now Considering AP is tangent at point A

then OA = Radius = 3.1 cm

AP = 6.2 cm given

∠OAP = 90° ( Tangent)

=> OP² = OA² + AP²

=> OP² = 3.1² + 6.2²

=> OP² = 3.1²(1 + 4)

=> OP² = 3.1² (5)

=> OP = 3.1√5 cm