Question

AP is perpendicular to BC and ABC is a right-angled triangle, right angle at A. What is the area (in
cm')
of AABC ?
15 cm
Р
B
+
16 cm​

Answer 1

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

2

1

×base×height=

2

1

×AB×AC

=

2

1

×5×12=30cm

2

Now, in ΔABC,

Area of triangle ABC=

2

1

×BC×AD

⇒30=

2

1

×13×AD

⇒ AD=

13

30×2

=

13

60

cm.