Question

AP is the angle bisector of angle BAC such that AP..1.. BC. ​

Answer 1

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Answer 2

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a) In ∆APB ≈ ∆APC

angle APB = angle APC = 90°

AP = AP (common)

BP = CP (mid point p)

∆APB ≈ ∆APC (SAS)

b) Yes, BP = CP

As it's given in that AP is perpendicular to BC. It means P is the mid point of side BC. Which divide the side into 2 equal parts.