AP is the tangent drawn from a point P to the circle of radius 3cm. If the length of the tangent is 4cm. If 0 is the centre of the circle, find PO
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From figure,
CA is perpendicular to AP and CB is perpendicular to BP
Again AC = BC = 4 (radius of the circle)
Also AP = PB = (Tangents from point P)
So, BPAC is a square.
=> AP = PB = BC = CA = 4 cm
So, length of tangents are 4 cm each
therefore option B will be the answer.
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