Question

AP = PB. then prove that AP =
AB
In the adjacent figure
EDICA ZBAC = 65°
DEC = 105
Find the value of and y.
IOS​

Answer 1

Answer:

please ask the question with diagram

Answer 2

Step-by-step explanation:

IN ∆APB AP=AB

SO,. ANGLE B = ANGLE P

NOW ,

ANGLE A+ANGLE B +ANGLE P=180

ANGLE A +ANGLE P ANGLE P=180

ANGLE A=180- 2ANGLE P

AS PER RULES (6.1)

ANGLE A = ANGLE P.........(1)

ANGLE P = ANGLE B

ANGLE B = ANGLE A

SO,

AP= AB {FROM (1) }