Question

AP the bisector of angle a of triangle ABC meet BC at P if the coordinate of b ,p,c are (1,-2),(2,1) and (4,7) respectively .find AB / AC

Answer 1

Here,∆ABC meet PC at P
.•.A(1,-2)=(X1,Y1)
B(2,1)=(X2,Y2)

.•.AB=Y2-Y1
X2-X1
=1-(-2)
2-1
=1+2=3
2-1=1
Here,AB=(3,1).

Here,C=(4,7)=(X2,Y2)
AC=Y2-Y1
X2-X1
=7-(-2)
4-1
=7+2=9{bcoz, 9 is divided
4-1=3 with 3 then ur ans
Will be 3,1}
=9
3
AC=3
1
.•.AC=(3,1).