Hindi, asked by nareshccc1994, 3 months ago

अपने जीवन से जुड़े संस्मरण को रचनाबद्ध कीजिए​

Answers

Answered by Anonymous
0

To find :

• Value of \sf x + \dfrac{1}{x} =?

Solution :-

Given ,

x = 4 - √15

\therefore\sf \dfrac{1}{x} = \dfrac{1}{4 - \sqrt{15}}

\\\\ \\ {\ \ \ \ \ }\rm{\star \ Rationalising \ the \ denominator : }

 : \implies\sf \dfrac{1}{x} = \dfrac{1(4 + \sqrt{15})}{(4 - \sqrt{15})(4 + \sqrt{15})} \\\\

: \implies\sf \dfrac{1}{x} = \dfrac{4 + \sqrt{15}}{4^2 - (\sqrt{15})^2}\\\\

 : \implies\sf \dfrac{1}{x} = \dfrac{4 + \sqrt{15}}{16 - 15} \\\\

 : \implies\sf \dfrac{1}{x} = \dfrac{4 + \sqrt{15}}{1} \\\\

 : \implies\underline{\boxed{\sf{\dfrac{1}{x} = 4 + \sqrt{15} }}}\\\\

____

: \implies\sf x + \dfrac{1}{x} = 4 - \sqrt{15} + 4 + \sqrt{15}\\\\

 : \implies\underline{\boxed{\bold{x + \dfrac{1}{x} = 8 }}} \\\\\

Requried value....

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