Question

Aparna borrowed Rs 8000 from a bank at 12% per annum for 3 years at simple interest

and Nanda borrowed the same amount for the same time period at 10% per annum

compound annualy. Who paid more interest?



pls solve on a paper and show​

Answer 1

Let the required time be t years. Then,

8000+8000×12×t=9100+9100×10×t

8000+960t=9100+910t

50t=1100

t=22 years..

Answer 2

$\star\underline{\mathtt\orange{⫷❥Q᭄} \mathfrak\blue{u~ }\mathfrak\blue{Σ} \mathbb\purple{ §}\mathtt\orange{T} \mathbb?\pink{iOn⫸}}\star\:$

Aparna borrowed Rs 8000 from a bank at 12% per annum for 3 years at simple interest

and Nanda borrowed the same amount for the same time period at 10% per annum

compound annualy. Who paid more interest?

${ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{✯꧁ ⋆᭄ SoLuTiOn⋆᭄꧂✯ }}}}}}$

$for \: ninda$

$p = 8000 \\ r = 10 \: percent \\ t = 3 \: years$

$formula \\ a = p {(1 + \frac{r}{100}) }^{t}$

$a = 8000 {(1 + \frac{10}{100} })^{3}$

$a = 10648$

$cl = a - p$

$cl = 10648 - 8000$

$cl = 2648$

$for \: aparna$

$p = 8000 \\ r = 12 \: percent \\ t = 3 \: years$

$si = \frac{prt}{100}$

$si = \frac{8000 \times 12 \times 3}{100}$

$si = 2880$

$aparna \: paid \: more \: intrest$

$\blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{☺︎︎Hope\:It\:Helps☺︎︎}}}}}}$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}$