Question

Aparna is on her way to school. She walks at a uniform speed of 1 m/s for 10 minutes , and then runs at a uniform speed of 5 m/s for 5 minutes. What is the total distance covered by Aparna?​

Answer 1

Answer:

Given side of square =10m, thus perimeter P=40m

Time taken to cover the boundary of 40 m =40 s

Thus in 1 second, the farmer covers a distance of 1 m

Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m

Now the total number of rotation the farmer makes to cover a distance of 140 meters =perimetertotaldistance

=3.5 

At this point, the farmer is at a point say B from the origin O

Thus the displacement s=102+102 from Pythagoras theorem.

s=102=14.14m 

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Answer 2

$Speed = \frac{Distance}{Time} \\ speed( {v}^{1}) = 1m {s}^{ - 2}$

$Time ( {t}^{1} ) = 10minutes = 600s$

We know that:-

$Distance( {d}^{1} ) = Speed( {v}^{1} ) \times Time( {t}^{1}) \\ Distance = 1 \times 600 = 600m$

Now,

$Speed( {v}^{2} ) = 5ms {}^{2} \\ Time( {t}^{2} ) = 5minutes = 300s \\ Distance( {d}^{2} )= 5 \times 300 = 1500m$

$Total \: Distance = {d}^{1} + {d}^{2} \\ Total \: Distance =600m + 1500m \\ Total \: Distance =2100m$

$\red{\tt{Total \: Distance =2100m}}$