Math, asked by chaithanyar235, 6 months ago

Apeksha purchased one dozen bangles. One day she slipped on the floor and fell down. What can be the ratio of broken to unbroken bangles:

3 : 5
5 : 3
2 : 3
1 : 5


Answers

Answered by arvindg4s1982
1

Answer:

eleven is the answer of broken and 1 is not broken

Answered by InfiniteSoul
10

\sf{\underline{\boxed{\large{\blue{\mathsf{Answer}}}}}}

  • Ratio of the broken bangles is 1 :5

\sf{\underline{\boxed{\large{\blue{\mathsf{Explanation}}}}}}

Total bangles = 1 dozen = 12

  • Option A

lets assume the ratio of broken to unbroken bangles is 3:5

Therefore ;

\sf\implies 3x + 5x = 12

\sf\implies 8x = 12

\sf\implies x = \dfrac{12}{8}

\sf\implies x = \dfrac{6}{4}

\sf\implies x = \dfrac{3}{2}

No. of x cannot be verified by this therefore our assumption was wrong .

  • Option B

lets assume the ratio of broken to unbroken bangles is 5:3

Therefore ;

\sf\implies 5x + 3x = 12

\sf\implies 8x = 12

\sf\implies x = \dfrac{12}{8}

\sf\implies x = \dfrac{6}{4}

\sf\implies x = \dfrac{3}{2}

No. of x cannot be verified by this therefore our assumption was wrong .

  • Option C

lets assume the ratio of broken to unbroken bangles is 2:3

Therefore ;

\sf\implies 2x + 3x = 12

\sf\implies 5x = 12

\sf\implies x = \dfrac{12}{5}

No. of x cannot be verified by this therefore our assumption was wrong .

  • option D

lets assume the ratio of broken to unbroken bangles is 1:5

Therefore ;

\sf\implies x + 5x = 12

\sf\implies 6x = 12

\sf\implies x = \dfrac{12}{6}

\sf\implies x = \dfrac{6}{3}

\sf\implies x = 2

No. of x can be verified by this therefore our assumption was Right .

_______________________

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