Question

apna thevirat bro krega yh question ❤️❤️

because meko uske alawa koi shi answer krta hi nii h ​

Answer 1

Step-by-step explanation:

let zeroes of polynomial be a and (-a).

so, we know

sum of zeroes = coefficient of x / coefficient of x^2

therefore, a+(-a) = 42k^2/14

0= 3k^2

0/3=k^2

k= 0

so, answer is k = 0.

please mark as brainest and follow me also

Answer 2

Given :

• One of the zeroes of the quadratic polynomial 14x² - 42k²x - 9 is negative of the other.

To Find :

• The value of k.

Solution :

Since the given polynomial is a quadratic, we will have two zeroes.

Let the one of the zeroes of the quadratic polynomial be x.

Given further, one zero is negative of the other.

•°• The second zero → - x

Since one zero is negative of the other, the sum of the zeroes will be 0. Any negative and positive value when added equals 0.

Sum of zeroes → 0 ___(1)

The relation between the coefficient and sum of zeroes is given as follows :

$\red{\longrightarrow}$ $\sf{Sum\:of\:zero\:=\:\dfrac{-(-b)}{a}}$

Compare the given quadratic polynomial with the general form.

•°• a = 14 , b = - 42k², c = - 9.

$\red{\longrightarrow}$ $\sf{Sum\:of\:zero\:=\:\dfrac{-(-42k^2)}{14}}$

$\red{\longrightarrow}$ $\sf{Sum\:of\:zero\:=\:\dfrac{42k^2}{14}}$

$\sf{Sum\:of\:zero\:=3k^2}$ ___(2)

From equation (1),

Sum of zeroes = 0

Comparing (1) and (2),

$\red{\longrightarrow}$ $\sf{0=3k^2}$

$\red{\longrightarrow}$ $\sf{\dfrac{0}{3}=k^2}$

$\red{\longrightarrow}$ $\sf{0=k^2}$

$\red{\longrightarrow}$ $\sf{\sqrt{0}=k}$

$\red{\longrightarrow}$ $\sf{k=0}$

$\large{\boxed{\sf{\green{Value\:of\:k\:=0}}}}$