Question

(APP)
(6) Mr. X deposited 10,000 in a Bank for 3 years offering interest @ 6%
compounded half yearly during first year, @ 12% compounded quarterly
during second year and @ 10% compounded continuously during third year.
Compute his balance after 3 years.
[2008 (R)
Sol. Required balance​

Answer 1

Answer:

$10000 \times (1 + \frac{6}{200} ) {}^{2} = 10609$

$10609 \times (1 + \frac{12}{400} ) {}^{4} = 11941$

$11941 \times (1 + \frac{10}{100} ) = 13135$

₹13135 is req. balance

Answer 2

Step-by-step explanation:

S = p(1+r/m)⁴*¹ (1 +r/m)²*²

(1+r/m)¹*³

= 10000 (1+0.10/4)⁴ (1+0.12/2)⁴ (1+ 0.03)³

=10000(1.025)⁴(1.06)⁴(1.03)³

=15226.08