Question

Apparent dips when dip circle is placed in two mutually perpendicular

Answer 1

Answer:

tan⁻¹ (√3/2)

Step-by-step explanation:

Missing point in question :-

Apparent dips when dip circle is placed in two mutually perpendicular directions are 30 and 45 degree What is actual dip at that place?

tan δ' = tan δ / cos α

where δ' - Apparent Dip, δ - True Dip, α - Angle between dip circle and magnetic meridian

tan 30 = tan δ / cos α

∴ cos α = tan δ / tan 30 -- (1)

45° is new apparent dip, here α' = α - 90

tan 45 = tan δ/ cos (α - 90)

∴ tan 45 = tan δ/ sin α

∴ sin α = tan δ/ tan 45 -- (2)

sin²α + cos²α  = 1

From 1 & 2, we get

tan²δ (1/3 +1 ) = 1

tan²δ = 3/4

δ = tan⁻¹ (√3/2)