Question

Apples cost l rupees per kilogram for the first 30 kilograms and q rupees per kilogram for each additional kilogram. If ashwin buys 33 kilograms of apples for rs.1167 and virat buys 36 kilograms of apples for rs.1284, then how much does mahendra pay in rupees for 10 kilograms of apples?

Answer 1

Answer:

10

Explanation:

Because the apples cost 1rs/kg for first 30 kg

Answer 2

Answer:

rs. 350

Explanation:

Cost for each kg for first 30 kgs = l

So, cost for 30kgs = 30×l

Cost for each additional kg = q

Let x be the number of additional kgs.

Therefore, total cost = 30l + xq

Case 1:

quantity = 33 kgs

additional quantity = 33-30 = 3kgs

Total cost = rs 1167

So, 30l + 3q = 1167..........eq.1

Case 2:

quantity = 36 kgs

additional quantity = 6kgs

Total cost = rs 1284

So, 30l + 6q = 1284.........eq.2

To find the cost of 10 kgs, the cost of 1 kg (l) should be known.

So, by elimination,

eq 1.......30l + 6q = 1284

eq 2.......30l + 3q = 1167

-------------------------

3q = 117

q = 117/3

q = 39

From eq.1, 30l + 3q = 1167

30l = 1167 - 108

l = 35

So, Cost of each kg = rs 35.

Cost of 10 kgs = 35 × 10

= rs 350.

Therefore,

Mahendra has to pay rs. 350 for 10kg of apples.