Question

Application
3
in some real-life situations, we use the addition or subtraction of mixed fractions.
Ajit ate 5 – biscuits and Arun ate 8
biscuits. How many biscuits did they eat
5
4
example 3:
in all? How many biscuits were remaining if the box had 20 biscuits in itę
Total number of biscuits in the box = 20
3
Number of biscuits eaten by Ajit = 5-
solution:
5
Number of biscuits eaten by Arun = 8-
4.
-
+
17
Total number of biscuits eaten by both Ajit and Arun
3 1
28
33 112+165 277 17
= 5 +8
= 13
5 4 5
4
20 20 20
20 277 400-277
Number of biscuits remaining = 20 - 13
20 1 20
20
123 3
[L.C.M. of 1 and 20 is 20.]
= 6
20 20
17
3
Therefore, Ajit and Arun ate 13
biscuits and 6 biscuits are remaining
20
20
2​

Answer 1

Answer:

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