APPLICATION BASED QUESTIONS
1)NINE SQUARES WITH SIDE LENGTHS 1,4,7,8,9,10,14,15 AND 18CM CAN BE FITTED TOGETHER WITH NO GAPE AND NO OVERLAPS TO FORM A RECTANGLE. WHAT ARE THE DIMENSION OF THAT RECTANGLE? ALSO FIND ITS PERIMETER AND AREA
PLEASE ANSWER CORRECTLY I WILL MARK AS YOU BRAINLEST
Answers
Answered by
2
Answer:
dimensions of rectangle=32 cm x33 cm
area of rectangle=1056 cm²
Perimeter=2*(32+33)
=2*65
=130 cm
Step-by-step explanation:
Total of area of squares
=1+16+49+64+81+100+196+225+324=1056
and we know 32 x33=1056so are of rectangle=1056 cm²
Perimetr=2*(32+33)
=2*65
=130 cm
Answered by
0
Answer:
Area of the rectangle is 1056cm².
Step-by-step explanation:
If 9 squares are to be fitted in a rectangle,
therefore, there areas will be same.
According to the Question,
Areas of the 9 squares = Area of the big rectangle
l×b = 1² + 4² + 7² + 8² + 9² + 10² + 14² + 15² + 18²
l×b = 1+16+49+64+81+100+196+225+324
l×b = 1056
Therefore, Area of the rectangle is 1056cm².
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