Math, asked by sanghamitrasamal, 3 months ago

APPLICATION BASED QUESTIONS

1)NINE SQUARES WITH SIDE LENGTHS 1,4,7,8,9,10,14,15 AND 18CM CAN BE FITTED TOGETHER WITH NO GAPE AND NO OVERLAPS TO FORM A RECTANGLE. WHAT ARE THE DIMENSION OF THAT RECTANGLE? ALSO FIND ITS PERIMETER AND AREA

PLEASE ANSWER CORRECTLY I WILL MARK AS YOU BRAINLEST​​​

Answers

Answered by Anonymous
2

Answer:

dimensions of rectangle=32 cm x33 cm

area of rectangle=1056 cm²

Perimeter=2*(32+33)

=2*65

=130 cm

Step-by-step explanation:

Total of area of squares

=1+16+49+64+81+100+196+225+324=1056

and we know 32 x33=1056so are of rectangle=1056 cm²

Perimetr=2*(32+33)

=2*65

=130 cm

Answered by Samarpita465
0

Answer:

Area of the rectangle is 1056cm².

Step-by-step explanation:

If 9 squares are to be fitted in a rectangle,

therefore, there areas will be same.

According to the Question,

Areas of the 9 squares = Area of the big rectangle

l×b = 1² + 4² + 7² + 8² + 9² + 10² + 14² + 15² + 18²

l×b = 1+16+49+64+81+100+196+225+324

l×b = 1056

Therefore, Area of the rectangle is 1056cm².

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