Question

application of derivative​

Answer 1

Answer:

(C) is the correct answer !!

Step-by-step explanation:

Given curve y = x² – 3x + 7

put x = 1

value of y = (1)² – 3 (1) + 7

y = 1 – 3 + 7

y = –2 + 7

y = 5

point is ( 1 , 5 )

To find the slope of the curve we need to differentiate.

Apllying derivative

y' = dy/dx = 2x – 3

Slope at x= 1

y' ( at x= 1 )

y' = 2(1) – 3

y' = 2 – 3

y' = – 1

Now equation of tangent at point (x1, y1) is given by

( y – y1 ) = slope ( x – x1 )

( y – 5 ) = – 1 ( x – 1) )

y – 5 = – x + 1

x + y – 5 – 1 =0

x + y – 6 = 0