Question

application of Markownikoff​

Answer 1

Answer:

When an unsymmetrical alkene reacts with a hydrogen halide to give an alkyl halide, the hydrogen adds to the carbon of the alkene that has the greater number of hydrogen substituents, and the halogen to the carbon of the alkene with the fewer number of hydrogen substituents. This is the statement of markovnikov’s rule.

This means that when an alkene is attacked by a hydrogen halide, the negative part of the reagent ( bromine here ) attacks the carbon with the least number of hydrogens attached to it. This is because propene is protonated ( added with a proton ) to give two types of carbocations - One is the primary and other is the secondary carbocation. Since the secondary carbocation is more stable the bromide ion then attaches itself to the secondary carbocation.

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