application of trignometry 16
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height of the tower= 6m
Step-by-step explanation:
Let h be the height of the tower
and let α be the angle of elevation
Since the angles are complementary, they add up to 90°.
Therefore, the angle of elevations are: α and 90-α
Refer to the drawing shown below.
tanα = h/4
tan(90-α) = h/9
According to trig identities,
tan(90-α) = cotα
Therefore,
cot α = h/9
1/ tan α = h/9
So, tan α = 9/h
Since tan α has two different values(that is h/4 and 9/h), make them equal.
So h/4 = 9/h
h^2 = 36
Therefore h= 6m
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