Question

APPLICATIONS OF DERIVATIVES
8.33
. (i) Determine the point on the curve y = 3x2 + 4 at which the tangent is perpendicular to a line whoseslope is-1by6​

Answer 1

Answer:

slope of line= -1/6

so slope of tangent =+1/6

but

slope = dy/dx=6x=+1/6

so

x=1/36

you can find now y easily by putting this value of x in equation of curve