Question

Apply division algorithm to find the quotient and remainder on dividing the polynomial 3 x cube + 4 x square + 6 X + 9 by 3 Cube + 2 X + 3 also verify the division algorithm

Answer 1

this circle part must be x cube
if it is x cube then answer I have given you

Answer 2

Answer:

Quotient = 3

Remainder = $4x^2$

Step-by-step explanation:

Dividend = $3 x^3+ 4 x^2+ 6x + 9$

Divisor = $3x^3+2x+3$

$Dividend = (Divisor\times quotient)+Remainder$

$3 x^3+ 4 x^2+ 6x + 9 = (3x^3+2x+3 \times 3)+4x^2$

So, quotient = 3

Remainder = $4x^2$

To Verify :

$3 x^3+ 4 x^2+ 6x + 9 = (9x^3+6x+9)+4x^2$

$3 x^3+ 4 x^2+ 6x + 9 = 9x^3+6x+4x^2+9$

So, LHS = RHS

Hence verified