Question

Apply Gauss theorem to find an expression for electric field intensity at any point due to a point charge

Answer 1

Explanation:

)Electric field intensity at any point outside a uniformly charged spherical shell:

Consider a thin spherical shell of radius R and with centre O. Let charge + q be uniformly distributed over the surface of the shell.

Let P be any point on the Gaussian sphere S1 with centre O and radius r, as shown in the following figure.

According to Gauss's law, we can write the flux through ds as:

At any point on the surface of the shell, r = R

Field lines when charge density of the sphere is positive

Field lines when charge density of the sphere is negative

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