apply kirchoffs law find i1 i2 and i3 in detail
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Applying Kirchhoff;s voltage law,
In loop I,−27−6I
2
−2I
1
+24=0
6I
2
+2I
1
=−3....(i)
In loop II,−27−6I
2
+4I
3
=0
6I
2
−4I
3
=−27....(ii)
At junction P,I
1
−I
2
−I
3
=0....(iii)
Solving equations (i), (ii) and (iii) we get
I
1
=3 A,I
2
=−3/2 A,I
3
=9/2 A.
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