Physics, asked by chennai80, 8 months ago

apply kirchoffs law find i1 i2 and i3 in detail​

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Answered by Tannupandit008
0

Answer:

Applying Kirchhoff;s voltage law,

In loop I,−27−6I

2

−2I

1

+24=0

6I

2

+2I

1

=−3....(i)

In loop II,−27−6I

2

+4I

3

=0

6I

2

−4I

3

=−27....(ii)

At junction P,I

1

−I

2

−I

3

=0....(iii)

Solving equations (i), (ii) and (iii) we get

I

1

=3 A,I

2

=−3/2 A,I

3

=9/2 A.

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