Apply Lagrange’s formula to find f ( ) 5 , given that f ( ) 1 2 = , f ( ) 2 4 = , f ( ) 3 8 = , f ( ) 4 16 = , f ( ) 7 128 =
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f(4)=(4–3)(4–5)(4–8)(4–12)(2–3)(2–5)(2–8)(2– 12)(10)+(4–2)(4–5)(4–8)(4–12) ... If the number of negative signs is odd (i.e. 1, 3, 5, 7, … etc.) (2)f(0) = -3, f(1)= -2 - 2 Sin 1 , f(2)= -1 - 2 Sin 2 ,f(3 )= - 2 Sin 3, f(4)= 1- 2 Sin 4 f(-2)= -5 + 2 Sin 2 ... f(0) = -7, f(1)= -7 , f(2)= 5 ... Using Lagrange Interpolation find the value of y at x=8. Given ...
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