Apply lens formula to determine the focal length of a convex lens which forms a three times magnified real image of an object placed 16 cm in front of it
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Given data:
f=?
u=16
v=?
Let object height be x
Image height=3x
3x/x=v/u
3x/x=v/16
3=v/16
3*16=v
48=v
Lens formula:
1/v-(-1/u)=1/f
1/v+1/u=1/f
1/16+1/48=1/f
1*3/16*3+1/48=1/f
3/48+1/48=1/f
4/48=1/f
48/4=f
12=f
focal length=12
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