Question

Apply POAC to solve this

Answer 1

Answer$

Valence factor of oxalic acid with respect to c is 1/2

Equivalent of oxalic acid = Equivalent of co

Moles*f=moles*f

10/63 * 1/2=moles * 1

10/126=moles

280/126 = weight

2.22 gm = weight

Equivalent =Equiavalent

Moles*f=moles*f

Moles*1/2=moles*1

10/126=moles

Weight =3.49 gm

By poac of h

moles of oxalic acid = moles of h20

170/60 = weight

2.8 gm = weight