Apply the division algorithm to find the quotient and remainder on dividing x3 - 6x2 + 11x - 6 by x+ 2
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Answered by
43
reminder 60
quotient is x²-8x+27
hope it help u...
quotient is x²-8x+27
hope it help u...
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Answered by
45
p(x) = x³ - 6x² + 11x -6
g(x) = x +2
Let q(x) = ax² + bx +c
Let r(x) = k
acc. to division algorithm
p(x) = g(x) * q(x) + r(x)
x³ - 6x² + 11x -6 = (x +2) * (ax² + bx +c) + k
x³ - 6x² + 11x -6 = ax³ + bx² +cx +2ax² +2bx +2c + k
x³ - 6x² + 11x -6 = ax³ + bx² +2ax² +2bx +cx +2c + k
x³ - 6x² + 11x -6 = ax³ + (b +2a)x² +(2b +c)x +2c + k
Equating the equation of like powers of x on both sides , we get
on equating the cofficients of x³
1 = a
on equating the cofficients of x²
-6 = 2a +b
-6 = 2 + b
-6 -2 =b
-8 = b
on equating the cofficients of x
11 = 2b +c
11 = -16 +c
11 + 16 = c
27 = c
on equating the constant term
-6 = 2c +k
-6 = 54 +k
-6 - 54 = k
-60 = k
solving these equation we get
a = 1
b = -8
c =27
k =-60
q(x) = x² -8x + 27
reminder = -60
g(x) = x +2
Let q(x) = ax² + bx +c
Let r(x) = k
acc. to division algorithm
p(x) = g(x) * q(x) + r(x)
x³ - 6x² + 11x -6 = (x +2) * (ax² + bx +c) + k
x³ - 6x² + 11x -6 = ax³ + bx² +cx +2ax² +2bx +2c + k
x³ - 6x² + 11x -6 = ax³ + bx² +2ax² +2bx +cx +2c + k
x³ - 6x² + 11x -6 = ax³ + (b +2a)x² +(2b +c)x +2c + k
Equating the equation of like powers of x on both sides , we get
on equating the cofficients of x³
1 = a
on equating the cofficients of x²
-6 = 2a +b
-6 = 2 + b
-6 -2 =b
-8 = b
on equating the cofficients of x
11 = 2b +c
11 = -16 +c
11 + 16 = c
27 = c
on equating the constant term
-6 = 2c +k
-6 = 54 +k
-6 - 54 = k
-60 = k
solving these equation we get
a = 1
b = -8
c =27
k =-60
q(x) = x² -8x + 27
reminder = -60
aishmeet:
very good
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