Physics, asked by john7494, 3 months ago

apply the first law of thermodynamics to determine the change in internal energy during boiling and melting process​

Answers

Answered by archanaram9001
2

Therefore, dW= P (dV) = P x 0 = 0. So, the internal energy during the melting process increases by (mL) at constant temperature. This is due to increase in internal potential energy (UP). The internal kinetic energy ( UK ) remains constant.

...

Adiabatic Process.

dQ = dU + dW = 0

or dU = – dW

Answered by saraswatishahde8
6

Answer:

Therefore, dW= P (dV) = P x 0 = 0. So, the internal energy during the melting process increases by (mL) at constant temperature. This is due to increase in internal potential energy (UP). The internal kinetic energy ( UK ) remains constant.

Similar questions