Apply The Properties Of Isosceles and equilateral Triangles To find the unknown angles in the given figure.
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(vi) In the Fig. (vi)
a = b (Angles opposite to equal sides)
∴ y = 120°
But a + 120° = 180° (Linear pair)
⇒ a = 180° – 120° = 60°
∴ b = 60°
But x + a + b = 180° (Angles of a triangle)
⇒ x + 60° + 60° = 180°
⇒ x + 120° = 180°
∴ x = 180° – 120° = 60°
B = z + 25
(Exterior angle of a triangle is equal to the sum of its interior opposite angles)
⇒ 60° = z + 25°
⇒ z = 60° – 25° = 35°
Hence x = 60°, y = 120° and z = 35°
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