Question

Applying a force of 20N, a body is moved through 10m in the direction of the force. Find the amount of workdone. A. 2000J B. 200J C. 320J​

Answer 1

Answer:

We have,

Long side of rectangular field is 60 meters more then the shorter side.

Let the longer side will be (y+30)mtr.

And the length of the diagonal will be (y+60) mtr.

Now, According to given question.

Using Pythagoras theorem,

(Diagonal)2=(shorterside)2+(longerside)2

(y+60)2=y2+(y+30)2

⇒y2+3600+120y=y2+y2+900+60y

⇒3600+120y−y2−900−60y=0

⇒−y2+60y+2700=0

⇒y2−60y−2700=0

⇒y2−(90−30)y−2700=0

⇒y2−90y+30y−2700=0

⇒y(y−90)+30(y−90)=0

⇒(y−90)(y+30)=

Answer 2

Question: Applying a force of 20N, a body is moved through 10m in the direction of the force. Find the amount of workdone.

Answer: B. 200J

Hope it Helps