Question

Applying a suitable identity find the product of (x-y),(x+y) and (x²+y²)

Answer 1

Answer:

(x-y)(x+y)(x2+y2)

(x^2-y^2)(x^2+y^2)

(x^4-y^4)

ANSWER

Step-by-step explanation:

using the identity x^2-y^2=(x+y)(x-y)

Answer 2

The product of (x-y),(x+y) and (x²+y²) is $=\textrm{x}^{4}-\textrm{y}^{4}$

Step-by-step explanation:

We have to find the product of $(\textrm{x+y}),(\textrm{x-y}),(\textrm {x}^{2}+\textrm{y}^{2})$

We know the identity $\left ( \textrm{x}+\textrm{y} \right )(\textrm{x}-\textrm{y })=\textrm{x}^{2}-\textrm{y}^{2}$

$(\textrm{x+y})\times(\textrm{x-y})\times(\textrm {x}^{2}+\textrm{y}^{2})$

$=((\textrm{x+y})\times(\textrm{x-y}))\times(\textrm {x}^{2}+\textrm{y}^{2})$

$=(\textrm{x}^{2}-\textrm{y}^{2})\times(\textrm {x}^{2}+\textrm{y}^{2})$

$=(\textrm{x}^{2})^{2}-(\textrm{y}^{2})^{2}$

$=\textrm{x}^{4}-\textrm{y}^{4}$

Therefore

$(\textrm{x+y})\times(\textrm{x-y})\times(\textrm {x}^{2}+\textrm{y}^{2})$ $=\textrm{x}^{4}-\textrm{y}^{4}$