Question

Applying quadratic equation solve
the equation :) (z-2)(z+4)=(-9)​

Answer 1

Answer:

(z-2)(z+4)= -9

opening the brackets

$z^{2} +4z-2z-8=-9\\z^{2}+2z+1=0\\z^{2} +z+z+1=0\\z(z+1)+1(z+1)=0\\(z+1)(z+1)=0\\z= -1$

there is 1 value of z which is -1

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