Question

approximate atomic weightvof an element is 26.89. If its equivalent weight is 8.9, the exact atomic weight of element would be_______

Answer 1

Hey Friend
Here is your answer

Equivalent weight = Atomic weight / Valancy
Valancy = Equivalent weight / Atomic weight
Valancy = 26.89 / 8.9
Valancy = 2.99
Exact Atomic Weight = Equivalent Weight * Valancy
Exact Atomic Weight = 8.9 * 2.99
Exact Atomic Weight = 26.611

Example of the exact atomic weight of :-
1)- Hydrogen = 1.00784 - 1.00811
2)- Helium = 4.002602
3)- Lithium = 6.938 - 6.997
4)- Beryllium = 9.0121831
5)- Boron = 10.806 - 10.821
6)- Carbon = 12.0096 - 12.0116
7)- Nitrogen = 14.00643 - 14.00728
8)- Oxygen = 15.99903 - 15.99977
9)- Fluorine = 18.998403163
10)- Neon = 20.1797

Hope this helped you
Have a nice day.

Answer 2

Answer:

Hey Friend

Here is your answer

Equivalent weight = Atomic weight / Valancy

Valancy = Equivalent weight / Atomic weight

Valancy = 26.89 / 8.9

Valancy = 2.99

Exact Atomic Weight = Equivalent Weight * Valancy

Exact Atomic Weight = 8.9 * 2.99

Exact Atomic Weight = 26.611

Example of the exact atomic weight of :-

1)- Hydrogen = 1.00784 - 1.00811

2)- Helium = 4.002602

3)- Lithium = 6.938 - 6.997

4)- Beryllium = 9.0121831

5)- Boron = 10.806 - 10.821

6)- Carbon = 12.0096 - 12.0116

7)- Nitrogen = 14.00643 - 14.00728

8)- Oxygen = 15.99903 - 15.99977

9)- Fluorine = 18.998403163

10)- Neon = 20.1797